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Formula for Complex Admittances in Parallel Given two admittances, Y1 = G1 + jB1 and Y2 = G2 + jB2, the net admittance Y of these in parallel is their vector sum, as follows:

(1115)

where R = p and p = [ 1 , x2 , x3 ] x If G, p, p, and p are each represented along the geographic frame north, east, and down axes, then pn = [0, 0, R] (1119)

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Y = (G1 + jB1 ) + (G2 + jB 2 ) = (G1 + G2 ) + j(B1 + B 2 ) The conductance and susceptance components add separately Just remember that if a susceptance is inductive, then it is negative imaginary in this formula

111 GRAVITATION AND SPECIFIC FORCE and eqn (1118) reduces to Gn pn 1 0 GM 0 1 R3 0 0 0 0 2

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When a coil, capacitor, and resistor are connected in parallel (Fig 16-7), the resistance should be thought of as a conductance, whose value in siemens (symbolized S) is equal to the reciprocal of the value in ohms Think of the conductance as all belonging to the inductor Then you have two vectors to add, when finding the admittance of a parallel GLC (conductance-inductance-capacitance) circuit: Y = (G + jBL ) + (0 + jBC) = G + j(BL + BC) Again, remember that BL is never positive! So, although the formulas here have addition symbols in them, you re adding a negative number when you add in an inductive susceptance

(1120)

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Continuing to neglect the ie ie p term from eqn (1114), we have 1 0 0 g 0 1 0 pn (1121) gn = R 0 0 2 where g = GM and gn = [ gn , ge , gd ] R2 The e ect of the gravity error on the velocity error dynamics is considered in detail in Section 1143 In that section, the vertical component of the position error is height above the ellipse h, not error in the down component d of the geodetic vector The fact that h = d inserts one extra negative sign in the error analysis of that section 1 0 0 n g 0 1 0 e (1122) gn = R 0 0 2 h The following two paragraphs brie y discuss simple models for the horizontal and vertical error dynamics The purpose is to introduce the important e ects that gravity has on the inertial system navigation systems In the navigation frame, the lateral position error di erential equations can be represented as = gn + n n = ge + e e where all error sources other than those due to gravity are combined into the terms n and e The full error model that de nes n and e will be discussed in Section 1141 From eqn (1122), gn = g n and ge = R g R e; therefore, the dependence of the lateral position error on the gravity error has the form + n g n R g + e e R = n = e

Problem 16-13 Suppose a resistor, a coil, and a capacitor are connected in parallel Suppose the resistor has a conductance G = 010 S, and the susceptances are jBL = j0010 and jBC = j0020 What is the complex admittance of this combination Consider the resistor to be part of the coil Then there are two complex admittances in parallel: 010 j0010 and 000 + j0020 Adding these gives a conductance component of 010 + 000 = 010 and a susceptance component of j0010 + j0020 = j0010 Therefore, the complex admittance is 010 + j0010

which are forced harmonic oscillators with natural frequency equal to the g Schuler frequency s = R If the gravity error terms were absent, then the lateral position errors would be the pure integral of the errors n and

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